Question

Find the remainder when x^3 +3x^2 +3x+1 is divided by x+1​

Answer 1

Answer:

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Answer 2

Answer:

By remainder theorem

By remainder theoremx+1=0

By remainder theoremx+1=0x=−1

By remainder theoremx+1=0x=−1p(x)=x

By remainder theoremx+1=0x=−1p(x)=x 3

By remainder theoremx+1=0x=−1p(x)=x 3 +3x

By remainder theoremx+1=0x=−1p(x)=x 3 +3x 2

By remainder theoremx+1=0x=−1p(x)=x 3 +3x 2 −3x−1p(−1)

By remainder theoremx+1=0x=−1p(x)=x 3 +3x 2 −3x−1p(−1)=(−1)

By remainder theoremx+1=0x=−1p(x)=x 3 +3x 2 −3x−1p(−1)=(−1) 3

By remainder theoremx+1=0x=−1p(x)=x 3 +3x 2 −3x−1p(−1)=(−1) 3 +3(−1)

By remainder theoremx+1=0x=−1p(x)=x 3 +3x 2 −3x−1p(−1)=(−1) 3 +3(−1) 2

By remainder theoremx+1=0x=−1p(x)=x 3 +3x 2 −3x−1p(−1)=(−1) 3 +3(−1) 2 −3(−1)−1

By remainder theoremx+1=0x=−1p(x)=x 3 +3x 2 −3x−1p(−1)=(−1) 3 +3(−1) 2 −3(−1)−1=−1+3(1)+3−1

By remainder theoremx+1=0x=−1p(x)=x 3 +3x 2 −3x−1p(−1)=(−1) 3 +3(−1) 2 −3(−1)−1=−1+3(1)+3−1=−1+3+3−1

By remainder theoremx+1=0x=−1p(x)=x 3 +3x 2 −3x−1p(−1)=(−1) 3 +3(−1) 2 −3(−1)−1=−1+3(1)+3−1=−1+3+3−1=6−2

By remainder theoremx+1=0x=−1p(x)=x 3 +3x 2 −3x−1p(−1)=(−1) 3 +3(−1) 2 −3(−1)−1=−1+3(1)+3−1=−1+3+3−1=6−2=4

By remainder theoremx+1=0x=−1p(x)=x 3 +3x 2 −3x−1p(−1)=(−1) 3 +3(−1) 2 −3(−1)−1=−1+3(1)+3−1=−1+3+3−1=6−2=4Thus remainder is 4

Step-by-step explanation:

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