Find the remainder when x
3 + 3x
2 + 3x + 1 is divided
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x-12
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Answered by
1
Answer:
8
Step-by-step explanation:
p(x) = x3 + 3x2 + 3x + 1
g(x) = x – 1
Let x – 1 = 0, then x = 1.
As per Remainder theorem, r(x) = p(x) = p(a)
p(x) = x3 + 3x2 + 3x + 1
p(1) = (1)3 + 3(1)2 + 3(1) + 1 = 1 + 3(1) + 3(1) + 1
= 1 + 3 + 3 + 1
P(1) = 8
∴ r(x) = p(x) = 8 ∴ Remainder is 8.
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