Question

find the remainder when x^3 - 3x^2+5x-1 is divided by x+1​

Answer 1

Answer:

the remainder will be x__ -1

if we put -1 then we will get -5+5 = 0

yes the remainder is 0

remainder 0

Answer 2

Hello Dear!!!

Here's your answer...

Given that,

p(x) = x^3 + 3x^2 - 5x +4

Zero of (x-2) is

x-2 = 0

x = 2

substitute the value of x in p(x)

p(2) = (2)^3 + 3(2)^2 -5(2)+4

p(2) = 8 + 3(4) - 10 +4

p(2) = 8+12-10+4

p(2) = 14

Remainder is 14.

OR

✪ Reminder theorem ✪

Let  be a polynomial of degree 1 or more and let  be any real number . If  is devided by  then reminder is .

✪ SOLUTION ✪

Let , x - 2 = 0.

Then, x = 2

Now,

P ( x ) = x³ + 3x² - 5x + 4

P ( 2 ) = 2³ + 3 × 2² - 5 × 2 + 4

P ( 2 ) = 8 + 12 - 10 + 4

P ( 2 ) = 24 - 10

P ( 2 ) = 14

Hence,

The reminder is 14.

_______________________

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