find the remainder when x^3+3x^+3x+1 is divided by x+1
Answers
Answered by
12
Answer :-
→ 0 .
Step-by-step explanation :-
By using remainder theorem .
We have,
→ p(x) = x³ + 3x² + 3x + 1 .
And, g(x) = x + 1 .
Let g(x) be the factor of p(x) .
Then, g(x) = 0 .
==> x + 1 = 0 .
x = -1 .
Now,
°•° p(x) = x³ + 3x² + 3x + 1 .
==> p(-1) = (-1)³ + 3(-1)² + 3(-1) + 1 .
= -1 + 3 - 3 + 1 .
= 0 .
Hence, remainder will be 0 .
Answered by
2
Answer:
By trail and error method
P(x) =x³+3x²+3x+1
= x +1 =0
= x= -1
P(-1)=(-1)³+3(-1)²+3(-1)+1
= -1 +3 -3 +1
remainder = 0
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