Question

Find the remainder when x^3+3x²+3x+1 is divided by 5+2x​

Answer 1

Answer:

let p(x) = x³ + 3x² +3x + 1

5 + 2x = 0

2x = -5

x = -5/2

Remainder = (-5/2)³ + 3 (-5/2)² + 3 (-5/2) + 1

-125/8 + 75/4 - 15/2 +1

-27/8 ans

Mark Brainliest if helped.

Answer 2

Answer:

Step-by-step explanation:

Let p ( x ) = x³ + 3x²+ 3x + 1

We can write divisor as 2x + 5.

If 2x+ 5 is divided by p ( x ) ,then 2x + 5 = 0 ⇒2x = - 5 ⇒ x = - 5/2.

On substituting,

p ( - 5/2 ) = ( - 5/2 )³ + 3 ( - 5/2 )² + 3 ( - 5/2 ) + 1

= ( - 125/8 ) + ( 75/4 ) - ( 15/2 ) + 1

= [ ( - 125 ) + ( 2 × 75 ) - ( 4 × 15 ) + ( 8 × 1 ) ] / 8

= ( - 125 + 150 - 60 + 8 ) / 8

= ( - 185 + 158 ) / 8

= - 27 / 8 is the answer.

∴ The remainder is - 27 / 8 .