Find the remainder when x 3+3x2+3x+1 is divided by (i) x+1 (ii) 5+2x (iii) x
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Answer:
Step-by-step explanation:
apply remainder theorem
5+2x=0
2x=-5
x=5/2
replace x by -5/2 , we get
x3+3x2+3x+1
= (-5/2)3+3(-5/2)2+3(-5/2)+1
= -125/8+75/4-15/2+1
= (-125+150-60+8)/125
= -27/8
therefore the remainder is -27/8
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