Question

Find the remainder when x^3 + 3x² +3x + 1 is divided by (x + π).​

Answer 1

Answer:

$x ^{3} + 3x ^{2} + 3x + 1 \div x + \pi \\ x + \pi = 0 \\ x = - \pi \\ \\ - \pi ^{3} + 3 (-\pi)^{2} + 3( - \pi) + 1 \\ = - \pi^{3} + 3\pi^{2} - 3\pi + 1$

Step-by-step explanation:

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