Question

find the remainder when (x^3-5x^2+x-5) is divided by 1-3x

Answer 1

p(x)=x³-5x²+x-5
g(x)=1-3x
-3x=-1
x=1/3
By remainder theorem ,
p(1/3)=(1/3)³-5*(1/3)²+1/3-5=1/27-5/9+1/3-5
=(1-15+9-135)/27= -140/27