Find the remainder when x^3 - 6x^2 + 2x - 4 is divided by 3x - 1
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Answer:
-107/27
Step-by-step explanation:
put x=1/3 in the polynomial
by using the remainder theorem
you will get the ans
remainder=1/3^3-6(1/3^2)+2/3-4
=1/27-2/3+2/3-4
=1/27-4
=-107/27
pgajpal11:
that is what i font know
dont
i updated the answer
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if x^3 + ax^2 - bx +10 is divisible by x^2 - 3x + 2 . Find the values of a and b
i have solved in the soln box
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