Math, asked by anandbarnwal430, 11 months ago

FIND THE REMAINDER WHEN (X^3-aX^2+6X-a) IS DIVIDED BY (X-a).​

Answers

Answered by sahilyadav54
1

Answer:

remainder = 5a

Step-by-step explanation:

zero of x-a = a

subsitute a in the place of x of dividend

a cube - a cube + 6a - a

5a

Answered by nidhisharma96
1

Answer:

x=a

p(x)=x^3-ax^2+6x-a

put x=a

p(a)=(a)^3-a(a)^2+6(a)-a

a^3-a^3+6a-a

5a

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