Question

find the remainder when x^3-ax^2+ 6x-a is divided by x-a​

Answer 1

Answer:

5a

Step-by-step explanation:

x-a=0

x=a

p(x)=

${x}^{3 } - a {x}^{2} + 6x - a$

p(a)=

${a}^{3} - a {a}^{2} + 6a - a$

${a}^{3} - {a}^{3} + 6a - a$

=5a