Find the remainder when x^3 -ax^2 +6x -a is divisible by x -a
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Answer:
5a
Step-by-step explanation:
Let's first find the zeros of the dividend g(x). In order to find the zeros of the g(x), we need to solve the equation g(x) = 0.
- g(x) or dividend is (x - a).
Transposing -a from L.H.S to R.H.S. Its sign will get changed.
Performing addition in R.H.S.
Now, by the remainder theorem, as we know that when p(x) is divided by (x - a) ,then the remainder is p(a).
Simplifying further.
Performing subtraction.
∴ The remainder is 5a.
*For verification, refer to the attachment! We've verified it using long division method.
Attachments:
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