Question

find the remainder when (x)3-(ax)2+bx-a is divided by x-a​

Answer 1

Answer:

hey mate

x-a=0

x= a

put the value of a

(x)³ - (ax)²+bx-a

a³-(a×a)²+ba-a

a³ - [(a)²]²+ba - a

a³-a^4+ba - a

so the remainder is

-a^4 +a³+ba+a

hope it will help you

Answer 2

Pls mark as brainliest answer