Question

find the remainder when x^3-ax+6x-a is divided by X-a​

Answer 1

Answer:

We have x

3

−ax

2

+6x−a

Apply remainder theorem

x−a=0

x=a

Put x=a in equation.

(a)

3

−a(a)

2

+6a−a

=a

3

−a

3

+6a−a

=6a−a

=5a

Then reminder is 5a