Question

Find the remainder when x^3-px^2+6x-p divided by x-p

Answer 1

$\star{\mathbb{\underline{ANSWER:}}}$

$let \: p(x) = {x}^{3} - p{x}^{2} + 6x - p$

$Divisor \: = x – p$

$Zero \:of \: x – p = p$

${By \:remainder \:theorem,}$

$If \:p(x) \:is \:divided \:by \:(x – p), \:then \:the \:remainder \:is \:p(p)$

$p ( p) = {p}^{3} - p ({p})^{2}+ 6 (p) -p$

$={p}^{3}-{p}^{3}+6p- p$

$= 6p - p$

$=5p$

Answer 2

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