Question

find the remainder when x^3-px^2+6x-p is divided by x - p​

Answer 1

Answer:

${x}^{3} - px {}^{2} + 6$

Step-by-step explanation:

To solve this we need split the term as much as possible so ,

we can write this as

$( {x}^{3} - px {}^{2} + 6x - p ) \: \div \: (x - p)$

so now we will expand all the term

$(x {}^{3} - p \: \times \: x {}^{2} + (3 \times 2)x - p \: \div \: x - p$

so in this x - p in the numerator and x - p in the denominator are common so we will remove that term as shown down

$(x {}^{3} - p \times x {}^{2} + (3 \times 2)) \: \div \: 1$

so our final answer is here

${x}^{3} - px {}^{2} + 6$

Answer 2

Answer:

Same to u

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