Question

find the remainder when x^3+x^2+x+1 divided by x-1/2 using remainder theorm

Answer 1

Answer:

p(x) = x^3+x^2+x+1

g(x) = x-1/2

since g(x) is zero

by remainder theorem ,

x - 1/2 =0

x=1/2

p(1/2)= 1/2^3 + 1/2^2+1/2+1

= 1/8 + 1/4 +1/2 +1

= 1/8 + 2/8 +4/8+8/8

=15/8

hence remainder is 15/8

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Answer 2

Answer:

Step-by-step explanation:

Zero of polynomial is

X-1/2=0

Hence,x=1/2

Putting value of x=1/2

P( 1/2)=(1/2)^3+1/2^2+1/2

=7/8

By remainder theorem we know that when p(x) is divided by x-a, then p(a) =r

Here p(a) =p(1/2)=7/8

Therefore remainder is 7/8