Question

Find the remainder when x^3+x^2+x+1 is divided by x-12 using remainder theorem.
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Answer 1

Answer:

Zero of x - 12 is (12).

Putting x = 12 , we get ,

P(x) = x^3 + x^2 + x + 1

P(12) = (12)^3 + (12)^2 + 12 + 1

= 1728 + 144 + 12 + 1

= 1872 + 13

= 1885

Hence , by remainder theorem , when x^3 + x^2 + x + 1 is divided by x - 12 , remainder obtained is 1885