Math, asked by bmsmahendrasingh, 6 months ago

Find the remainder when x + 3x + 3x + 1 is divided by
x+π​

Answers

Answered by Anonymous
7

Given:

  • p(x) = x³ + 3x² + 3x + 1
  • g(x) = (x + π)

Solution:

Let p(x) = x³ + 3x² + 3x + 1 and g(x) = (x + π)

Now,

g(x) = 0 => x + π = 0

x = - π

By the remainder theorem, we know that when p(x) is divided by (x + π) then the remainder is p().

And,

p(-π) = (-π)³ + 3 × (-π)² + 3 (-π) + 1

-π³ + 3π² - 3π + 1

Therefore;

The Required remainder is ( -π³ + 3π² - 3π+1 ) .

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