Find the remainder when x + 3x + 3x + 1 is divided by
x+π
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Given:
- p(x) = x³ + 3x² + 3x + 1
- g(x) = (x + π)
Solution:
Let p(x) = x³ + 3x² + 3x + 1 and g(x) = (x + π)
Now,
g(x) = 0 => x + π = 0
x = - π
By the remainder theorem, we know that when p(x) is divided by (x + π) then the remainder is p(-π).
And,
↬ p(-π) = (-π)³ + 3 × (-π)² + 3 (-π) + 1
↬ -π³ + 3π² - 3π + 1
Therefore;
The Required remainder is ( -π³ + 3π² - 3π+1 ) .
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