Find the remainder when x^4 +x^3 -2x^2 +x +1 is divided by x -1
Answers
Answer:
2
Step-by-step explanation:
Take P(x) =X^4+X^3-2X^2+X+1
By Remainder Theorem when divided by X-1 the remainder is P(1)
that is X-1=0 so X = 1.
P(1) = (1)^4+(1)^3-2(1)^2+1+1 = 1 + 1 - 2 + 1 + 1 = 2
To find the remainder when x^4 + x^3 – 2x^2+ x + 1 is divided by x – 1, we can use synthetic division.
First, we write the coefficients of the polynomial in decreasing order of exponents and place a placeholder for the divisor x – 1:
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1 1 -2 1 1
1 |
Next, we bring down the first coefficient, which is 1:
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1 1 -2 1 1
1 | 1
Then, we multiply 1 by the divisor x – 1, which gives us x – 1:
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1 1 -2 1 1
1 | 1
-
0
Subtracting 0 from 1 gives us 1, which we bring down:
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1 1 -2 1 1
1 | 1 1
-
0 ...
We continue this process until we have brought down all the coefficients:
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1 1 -2 1 1
1 | 1 1 0 -2 3
-
0 1 -1 3 -2
Therefore, the remainder when x^4 + x^3 – 2x^2+ x + 1 is divided by x – 1 is 3.
Therefore, the correct option is (A) 3.