Question

find the remainder when x^4 + x^3 - x^2 -122x -150 divided by x - 5​

Answer 1

Step-by-step explanation:

by reminder theorum

x-5=0

x=5

p(x) = 5

5^4+5^3-5^2-122×5-150

625+125-25-70-150

750-95-150

750-245

505 is your reminder

Answer 2

Answer:

Remainder = -35

Step-by-step explanation:

P(x)= x⁴ + x³ - x² - 122x - 150

x - 5=0 → x = 5

P(5) = 5⁴ + 5³ - 5² - 122×5 - 150

P(5)= 625 + 125 - 25 - 610 - 150

P(5)= 750 - 785

P(5)= -35