find the remainder when x^+4x^2-5x^2-6x+7 when divided by x+1
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= 15.
Solution:
Given polynomial f(x) = x⁴ + 4x³ - 5x² - 6x + 7is divided by x - 1. And the Zero of x - 1 is...
→ x - 1 = 0
→ x = + 1.
Remainder is f(1),
f(x) = (1)⁴ + 4(1 )³ - 5(1 )² - 6(1 ) + 7
= 4 + 4( 3) - 5( 2) - 6 + 7
= 4 + 12 - 10 - 6 + 7
= 21 - 16
= 15.
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