Question

find the remainder when x^5-3x^4-ax^3+3ax^2+2ax-4 is divided by (x-2)​

Answer 1

Answer:

8a-20

Step-by-step explanation:

let p(x) =  x^5-3x^4-ax^3+3ax^2+2ax-4

to find remainder when p(x) / (x-2), use remainder theorem

⇒ p(2) is the remainder

ie, p(2) = (2)^5 - 3(2)^4 - a (2)^3 +3a (2)^2 + 2a (2) - 4

           = 32 - 48 - 8a + 12a + 4a -4

           = 8a-20