Question

Find the remainder when x cube + 3 X square + 3 X + 1 divided by x minus 1 upon 2

Answer 1

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p(x)=x³ + 3x² +3x +1

divisor=x-1/2

x-1/2=0

x=1/2

at x =1/2

p(1/2)=(1/2)³ + 3(1/2)² + 3(1/2) + 1

=1/8+3/4+3/2+1

=1/8+6/8+12/8+8/8

=27/8

Answer 2

p(x)=x³ + 3x² +3x +1

divisor=x-1/2

x-1/2=0

x=1/2

at x =1/2

p(1/2)=(1/2)³ + 3(1/2)² + 3(1/2) + 1

=1/8+3/4+3/2+1

=1/8+6/8+12/8+8/8

=27/8