Question

find the remainder when x cube + 3 X square + 3 X + 1 is divided by x minus one by two ​

Answer 1

Here is your answer

p(x) = {x}^{3} + 3 {x}^{2} + 3x + 1 \\ g(x) = x - 1 \\ g(1) = 0 (because 1 - 1 = 0) by factor theorm putting

x = 1 in equation = {(1)}^{3} + {3(1)}^{2} + 3(1) + 1 1 + 3 + 3 + 1 = 8

8 is remainder