find the remainder when x cube + 3 X square + 3 X + 1 is divided by X + π
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2
Using remainder theorem,
Let pie=$
X+$=0
X=-$
Put the value of x in polynomial given
(-$)cube+3×$square-3$+1
Solve these to get answer
Let pie=$
X+$=0
X=-$
Put the value of x in polynomial given
(-$)cube+3×$square-3$+1
Solve these to get answer
Answered by
5
Hope it helps.
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