Question

find the remainder when x cube + 3 X square + 3 X + 1 is divided by X using long division method​

Answer 1

$\textbf{Given:}$

$\textsf{Polynomial is}$

$\mathsf{x^3+3x^2+3x+1}$

$\textbf{To find:}$

$\textsf{The remainder when}\;\mathsf{x^3+3x^2+3x+1\;is\;divided\;by\;x}$

$\textbf{Solution:}$

$\textbf{We apply long division method to do the division}$

$\begin{array}{r|l}&x^2+3x+3\\\cline{2-2}x&x^3+3x^2+3x+1\\&x^3\\\cline{2-2}&****3x^2\\&****3x^2\\\cline{2-2}&*******3x\\&*******3x\\\cline{2-2}&*********1\\\cline{2-2}\end{array}}$

$\textsf{From this divisioin}$

$\mathsf{Quotient=x^2+3x+3}$

$\mathsf{Remainder=1}$

$\textbf{Find more:}$

By using long division method show that x minus 3 is a factor of 6 + X - 4 x square + x cube​

https://brainly.in/question/14713178

What should be subtracted from the polynomial x + 2x + 8x +22x + 18 so that it is completely divisible

by x2 + 6 ?​

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