Question

find the remainder when X cube +3 X square +3 X +1 is divided by X. - 1 upon 2​

Answer 1

Answer:

27/8 = Remainder

Step-by-step explanation:

p(x) = x^3+3x^2+3x+1

If x - 1/2 is a factor of p(x)

then,

x - 1/2=0

x=1/2

put x = 1/2 in p(x)

= x^3+3x^2+x+1

= (1/2)^3+3(1/2)+3(1/2)+1

= 1/8+3/4+3/2+1

Take the LCM

= 1 + 6 + 12 + 8/8

= 27/8 = Remainder