find the remainder when x cube + 3 X square + 3 X + 1 is divided by X + 22/7
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5
this is your answer......
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Answered by
1
Answer:
- 9.84
Step-by-step explanation:
Remember: Dividend = divisor x quotient + remainder
Divident = x cube + 3 X square + 3 X + 1
Divisor = X + 22/7
Quotient = we don't know this and we don't need to.....let it be equal to Q
Remainder = we have to find it
therefore equation becomes:
x cube + 3 X square + 3 X + 1 = ( X + 22/7 )(Q) + remainder
Now let X = -22/7, because when you put this in the equation , note that the divisor will become 0 and when it will multiply with Q, it will also become 0. So only the remainder will be left on the right side. Now calculate the left side,
(-22/7) cube +3(-22/7)square +3(-22/7) +1
= - 9.84
So, as left hand side = right hand side
therefore, -9.84 = remainder
So the remainder is -9.84
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