Question

find the remainder when x cube+3x square+3x+1 is divided by 5+2x​

Answer 1

Step-by-step explanation:

Let the x^3+3x^2+3x+1 be f(x)

now let 5+2xbe g(x)

by remainder theorem

g(x)=0

5+2x=0

x=-5/2

now by remainder theorem f(-5/2)

:-(-5/2)^3+3(-5/2)^2+3(-5/2)+1

= -125/8+75/4-15/2+1

=(-125+150-60+8)/8

=-27/8

Answer 2

Answer:

Step-by-step explanation:

Let the x^3+3x^2+3x+1 be f(x)

now let 5+2xbe g(x)

by remainder theorem

g(x)=0

5+2x=0

x=-5/2

now by remainder theorem f(-5/2)

:-(-5/2)^3+3(-5/2)^2+3(-5/2)+1

= -125/8+75/4-15/2+1

=(-125+150-60+8)/8

=-27/8