Question

find the remainder when x cube- 3x square + x + 1 divided by x-3​

Answer 1

Answer:

Let x - 3 = then x = 3

So, putting value of x in equation

X^3 - 3x^2 +x + 1

(3)^3 - 3(3)^2 + 3 + 1

27 - 27 + 4

0 + 4

4

So, using remainder theorem 4 is remainder

Step-by-step explanation:

HOPE IT HELPS YOU

Answer 2

Answer:

x³-3x²+x+1/x-3

zero of x-3=> x-3=0=> x=3

now putting the value of zero of x-3 in the given equation

so, (3)³-3(3)²+(3)+1

= 27-27+3+1

=4

Step-by-step explanation:

hope it helped you