Question

find the remainder when x cube-ax square +6x-a is divided by x-a​

Answer 1

Answer:

Apply remainder theorem

=>x – a =0

=> x =  a

Replace x by  a we get

=> x3 – ax2 + 6x – a

=>( a)3 -a(a)2 + 6(a) - a

=>  a3sup> – a3 + 6a – a

=>  5a

Remainder is 5a