find the remainder when x cube minus 3 X square + 2 X + 3 is divided by 2 X + 3
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Step-by-step explanation:
f (x)=x^3-3x^2+2x+3
f (x)=2x+3
f (x)=-3/2
f (-3/2)=(-3/2)^3- 3 (-3/2)^2+2 (-3/2)+3
f (-3/2)=-27/8-3 (-9/4)+2 (-3/2)+3
f (-3/2)=(-27/8)+27/4+0
f (-3/2)=(-27/8)+54/8+0
f(-3/2)=27/8
The remainder is 27/8
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