find the remainder when x cube minus 5 x square + 7 x + 11 is divided by x-1
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Let p(x) = 3x3 - 4x2 + 7x - 5
When p(x) is divided by (x - 3) the remainder is p(3)
Put x = 3 in p(x)
p(3) = 3(3)3 - 4(3)2 + 7(3) - 5
= 81 - 36 + 21 - 5 = 61
Similarly try for (x + 3)
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