Question

find the remainder when x cube minus a x square + 6 x minus a is divided by x minus afind the remainder when x cube minus 8 x square + 6 x minus A is divided by x minus A by using remainder theorem ​

Answer 1

Answer:

$x ^{3} - ax ^{2} + 6x - a$

$x (a) = a ^{3} - a(a) ^{2} + 6a - a$

$5a$

x (A) = A³ - 8A² +6A -A

Answer 2

Answer:

hope you get your answer

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