Question

find the remainder when x cube minus a x square plus 6x-5a is divided by X-a​

Answer 1

Answer:

f(x)=x-a=0

   = x=a

So,

p(x)=x^3-ax^2+6x-5a

then,

p(a)=a^3-a(a)^2+6a-5a

     = a^3-a^3+6a-5a

     =a

Therefore, the remainder will be a

Answer 2

I hope it helps u buddy!!!