Question

find the remainder when x power 4 plus x power 3 minus 2 X square + X + 1 is divided by x minus one ( plzz and this with explanation)​

Answer 1

Answer:

2

Step-by-step explanation:

$x {}^{4 } + {x}^{3} - 2 {x}^{2} + x + 1 \div x - 1$

Let

$p(x) = {x}^{4} + x {}^{3} - 2{x}^{2} + x + 1$

$f(x) = x - 1$

$x - 1 = 0$

$x = 1$

$p(1) = {1}^{4} + {1}^{3} - 2( {1}) ^{2} + 1 + 1$

$p(1) = 1 + 1 - 2 + 1 + 1$

$p(1) = 4 - 2$

$p(x) = 2$