Question

find the remainder when x square - 5 divided by x-1​

Answer 1

Answer:

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Answer 2

Answer:

Remainder is -4

Step-by-step explanation:

p(x) = $x^{2}-5$

a(x) = x - 1

Root of a(x)

  x-1=0

   x=1

So zero of a(x) is 1.

According to Remainder theorem, when p(x) is divided by a(x) = x-a, then p(a) is the remainder.

Therefore,

$p(1) = 1^{2}-5$

p(1) = -4

Therefore, remainder is -4

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