find the remainder when (x*x*x+3x*x+3x+1)/x-1/2
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according to given sum,
by remainder theorem .
x-1/2=0
x=1/2
substitute the value of x in the given polynomial. we get

1/2×1/2×1/2+3×1/2×1/2+3×1/2+1
=1/8+3/4+3/2+1
(1+6+12+8)/8
27/8.
:-)hope it helps u.
by remainder theorem .
x-1/2=0
x=1/2
substitute the value of x in the given polynomial. we get
1/2×1/2×1/2+3×1/2×1/2+3×1/2+1
=1/8+3/4+3/2+1
(1+6+12+8)/8
27/8.
:-)hope it helps u.
MrSharani:
right
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