find the remainder when X2+3x+2 is divided by x+1
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By remainder theorem
p(-1)= (-1)^2+3(-1)+2=0
So x+1 is a factor of p(x)
p(-1)= (-1)^2+3(-1)+2=0
So x+1 is a factor of p(x)
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Dividing x^2+3x+2 by x+1
Step-by-step explanation:
x+1÷x^2+3x+2
as division is given in the attached file...
Therefore the remainder is 0
Hope it helps you
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