Find the remainder, when x² + 4x³ - 5x² - 6x + 7 is divided by x-3
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Now, by remainder theorem, we have,
p(x) = x⁴ + 5x³ – 3x² + 4x + 3
p(-2) = (-2)⁴ + 5(-2)³ – 3(-2)² + 4(-2) + 3
p(-2) = 16 + 5(-8) – 3(4) + 4(-2) + 3
p(-2) = 16 -40 –12 -8 + 3
p(-2) = 19 – 60
p(-2) = –41.
Hence, remainder = –41
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