Question

Find the remainder when x²³-ax² +6x-a is divided by x-a.​

Answer 1

Answer:

Step-by-step explanation:

by using substituting method

x-a=0

x=a

sub in the equation

a^23-a[a^2]+6[a]-a

= a^23-a^3+5a

Answer 2

Answer:

We have x

3

−ax

2

+6x−a

Apply remainder theorem

x−a=0

x=a

Put x=a in equation.

(a)

3

−a(a)

2

+6a−a

=a

3

−a

3

+6a−a

=6a−a

=5a

Then reminder is 5a