Math, asked by AshishRozer, 1 month ago

Find the remainder when x³+2x²-x+3 is divided by 4x-1
please help me ​

Answers

Answered by shashankcreations
1

4x-1)x³+2x²-x+3(

question is wrong/incomplete

4x-1 cannot be divided by x³ + 2x² it should start with 4

Answered by AwesomeBoy
1

 \huge { \red { \boxed { \bf \blue{ \frac{41}{64} }}}}

Step-by-step explanation:

Let,

p(x) = + 2x² - x + 3

.

Now,

4x - 1 = 0

=> 4x = 1

=> x = 1/4

.

Put the value of x in p(x),

  \bf= >  p( \frac{1}{4} ) = ( \frac{1}{4}  {)}^{3}  + 2 {( \frac{1}{4}) }^{2}  -  \frac{1}{4}  + 3

 \\  \bf=  >  \frac{1}{64}  +  \cancel{2 }\bigg( \frac{1}{ \cancel{16}_{8} }  \bigg) -  \frac{1}{4}  + 3 \\  \\  \bf =  >  \frac{1 + 8 - 16}{64}   + 3 \\  \\  =  >  \bf \frac{ - 7}{64}  + 3 \\  \\  \bf =  >  \frac{ - 7 + 48}{64}  \\  \\  =  >    \red{\bf \frac{41}{64} }

So,

The remainder is 41/64.

Hope it helps.

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