find the remainder when x³+ 3 X²+3x+ 1 is divided by X + 1
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Remainder will be 0
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Find the remainder when x^3+3x^2+3x+1 is divided by X+1
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By remainder theorem
x+1=0
x=−1
p(x)=x^3 +3x^2−3x−1p(−1)
=(−1)^3 +3(−1)^2 −3(−1)−1
=−1+3(1)+3−1
=−1+3+3−1
=6−2
=4
Thus remainder is 4
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