Question

find the remainder when x³+3x²+1 is divided by x—½ ,x ,x+π​

Answer 1

Answer:

Answer:x-½=0

Answer:x-½=0 x=½

Answer:x-½=0 x=½ p(x)=x³+3x²+1

Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1

Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 =⅛+¾+1

Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 =⅛+¾+1 =15/8

Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 =⅛+¾+1 =15/8x+π=0

Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 =⅛+¾+1 =15/8x+π=0x=π

Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 =⅛+¾+1 =15/8x+π=0x=π π=22/7

Answer:x-½=0 x=½ p(x)=x³+3x²+1 p(½)=( ½)³+3.(½)²+1 =⅛+¾+1 =15/8x+π=0x=π π=22/7p(x)=x³+3x²+1

p(22/7)=( 22/7)³+3.(22/7)²+1

= 31.04(approx) + 29.61 +1

= 61.65(approx)