Question

find the remainder when x³-3x²+2x+1 divided by x=-1​

Answer 1

Step-by-step explanation:

Apply remainder theorem

=>x + 1 =0

=> x = - 1

Replace x by – 1 we get

=>x3+3x2 + 3x + 1

=>(-1)3 + 3(-1)2 + 3(-1) + 1

=> -1 + 3 - 3 + 1

=> 0

Remainder is 0

Answer 2

Answer:

-5

Step-by-step explanation:

${x}^{3} - 3 {x}^{2} + 2x + 1 \\ {x}^{2} (x + 1) - 4 {x}^{2} + 2x + 1 \\ {x}^{2} (x + 1) - 4x(x + 1) + 6x + 1 \\ {x}^{2} (x + 1) - 4x(x + 1) + 6(x + 1) - 5 \\ (x + 1)( {x}^{2} - 4x + 6) - 5 \\ \\ remainder \: = - 5 \\ \\ hope \: it \: will \: help \: you \:$