find the remainder when x³-3x²+3x-1 is divided by (1) x-1/2 (2) x+3. (3) x
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x=1/2
(1/2)^3-3(1/2)^2+3(1/2)-1
(1/8)-(3/4)+(3/2)-1
(1-6+12-8)/8
-(1/8)
(1/2)^3-3(1/2)^2+3(1/2)-1
(1/8)-(3/4)+(3/2)-1
(1-6+12-8)/8
-(1/8)
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