Question

Find the remainder when x3+3x2+3x+1 is divided by
(i) x+1
​

Answer 1

Answer:

The answer is 0

Step-by-step explanation:

By remainder theorem

x+1=0

∴ x=-1

Let p(x)= x^3+3x^2+3x+1x

3

+3x

2

+3x+1

p(-1)= (-1)^3+3(-1)^2+3(-1)+1(−1)

3

+3(−1)

2

+3(−1)+1

= -1+3-3+1

= 0

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Answer 2

$\huge\red{ꪖꪀᦓ᭙ꫀ᥅}$

$x+1= 0$

⇒$x = −1$

∴Remainder:

$p(−1) = (−1)^3+3(−1)^2+3(−1)+1$

$= −1+3−3+1$

$= 0$