Question

find the remainder when x³+3x²+3x+1 is divided by X + 1​

Answer 1

• On dividing (x³ + 3x² + 3x + 1) by (x + 1), we get, no remainder or zero(0) remainder.

Verification :

$= > {x}^{3} + {3x}^{2} + 3x + 1 \\ = > {x}^{3} + {x}^{2} + {2x}^{2} + 2x + x + 1\\ = > {x}^{2} (x + 1) + 2x(x + 1) + 1(x + 1) \\ = > (x + 1) \{ {x}^{2} + 2x + 1 \} \\ = >(x + 1) \{ {x}^{2} + x + x + 1\} \\ = > (x + 1) \{x(x + 1) + 1(x + 1) \} \\ = > (x + 1) \{ (x + 1)(x + 1)\} \\ = > (x + 1)(x + 1)(x + 1)$

• As the factors of (x³ + 3x² + 3x + 1), is (x + 1),(x + 1),(x + 1) thus, it is (x + 1)³

Answer 2

Answer:

hey mate here is ur answer

Step-by-step explanation:

by remainder theorem :

=> x+1=0 => x=-1

=>p(x)= x³+3x²- 3x-1p(-1)

=>(-1)³+3 (-1)²- 3(-1) -1

=>-1+3(1)+3-1

=> -1+3+3-1

=>6-2

=> 4

thus remainder is 4..

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