Find the remainder when x3 + 3x2 + 3x + 1 is divided by
x + 1
Answers
Answered by
1
Answer:
x+1 ) x^3 + 3x^2 + 3x +1 ( x^2 + 2x + 1
+x^3 + x^2
- -
__________
0 + 2x^2 + 3x +1
+ 2x^2 + 2x
- -
_____________
0 + x + 1
+ x + 1
- -
_________
0
the remainder will be 0
By another way ,
x+1 =0
x= (-1)
now evaluating the value of x
x^ 3 + 3x^2 + 3x + 1
(-1)^3 + 3(-1)^2 +3(-1) + 1
-1 +3 -3 +1
= 0
Hope it helps you
Answered by
0
Answer:
The remainder is 0.
Step-by-step explanation:
Let p(x) = x³ + 3x² + 3x + 1
x+1 = 0 ⇒ x = -1
∴ Remainder
= p(-1) = (-1)3 + 3(-1)2 + 3(-1) + 1
= -1 + 3 - 3 + 1
= 0
Therefore, The remainder is 0.
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